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Ratio Of Voltage Sensitivity And Current Sensitivity
Ratio Of Voltage Sensitivity And Current Sensitivity. Voltage sensitivity = q v current sensitivity = q i also, potential difference, v = ig hence, v s i s = q / v q / i = i v = i ig ∴ v s i s = 1 g This leads to units of v/w (volts per watt).
Conversion of instantaneous current into voltage requires that the detector capacitance c d discharge much quicker than the charge collection time of the detector. Where g is the galvanometer resistance. After avalanche multiplication, each primary carrier injected into an apd’s multiplier may yield a different number of secondary carriers.
Current Sensitivity = Voltage Sensitivity = If Current Sensitivity Increases And The Resistance Also Increases In Same Order, The Voltage Sensitivity Will Remain Unchanged.
The ratio of voltage sensitivity ( v_svs ) and current sensitivity ( isi_sis ) of a moving coil galvanometer is (g =conductance) moving coil galvanometer Gage block calibration and the coefficient of linear thermal expansion Hence, there is no increase in voltage sensitivity.
Conversion Of Instantaneous Current Into Voltage Requires That The Detector Capacitance C D Discharge Much Quicker Than The Charge Collection Time Of The Detector.
However, this increases the resistance of the coil also(r is proportional to length of conductor). The length and gauge of the wire must be considered in order to avoid exceeding the maximum burden. The above relation implies that if current sensitivity increases as well as the resistance increases in same order, the voltage sensitivity will remain unchanged.
Therefore We Write, Sensitivity = Dθ/Di.
For moving coil meter m 1: Excess multiplication noise results from the stochastic nature of the impact ionization process that amplifies the apd’s primary current. Using your recorded data, calculate the difference of the two voltage measurements and the two current set points.
Moving Coil Galvanometer Is An Electromagnetic Device That Can Measure Small Values Of Current.
`v_(s_2) = (n_2b_2a_2)/(k_2r_2)` and, voltage sensitivity for m 1 is given as: Sensitivity (m) = (𝑉 ∗ 𝑉𝑖 ) 𝑉𝑒𝑥∗ 𝐷 (7) where v out is the output emf of lvdt, v in is the input voltage from the main, v ex Current sensitivity does not depend upon resistance(r), whereas voltage sensitivity does, as evident from their expressions.
This Is Because The Resistance Of The Coil Is Dependent On Factors Like The Length And Area Of The Coil.
(8.1.9) v out ∝ i s. As we know that voltage sensitivity θ/v = (nab /k)(1/r); (b) voltage sensitivity for m 2 is given as:
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